5z^2(z+4)=4z^2-12z-128

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Solution for 5z^2(z+4)=4z^2-12z-128 equation: 


Simplifying
5z2(z + 4) = 4z2 + -12z + -128

Reorder the terms:
5z2(4 + z) = 4z2 + -12z + -128
(4 * 5z2 + z * 5z2) = 4z2 + -12z + -128
(20z2 + 5z3) = 4z2 + -12z + -128

Reorder the terms:
20z2 + 5z3 = -128 + -12z + 4z2

Solving
20z2 + 5z3 = -128 + -12z + 4z2

Solving for variable 'z'.

Reorder the terms:
128 + 12z + 20z2 + -4z2 + 5z3 = -128 + -12z + 4z2 + 128 + 12z + -4z2

Combine like terms: 20z2 + -4z2 = 16z2
128 + 12z + 16z2 + 5z3 = -128 + -12z + 4z2 + 128 + 12z + -4z2

Reorder the terms:
128 + 12z + 16z2 + 5z3 = -128 + 128 + -12z + 12z + 4z2 + -4z2

Combine like terms: -128 + 128 = 0
128 + 12z + 16z2 + 5z3 = 0 + -12z + 12z + 4z2 + -4z2
128 + 12z + 16z2 + 5z3 = -12z + 12z + 4z2 + -4z2

Combine like terms: -12z + 12z = 0
128 + 12z + 16z2 + 5z3 = 0 + 4z2 + -4z2
128 + 12z + 16z2 + 5z3 = 4z2 + -4z2

Combine like terms: 4z2 + -4z2 = 0
128 + 12z + 16z2 + 5z3 = 0

The solution to this equation could not be determined.

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